A derivation of the Rayleigh integral formulation is given in Pierce
[9]. In brief, it relates the velocity potential j(p)
at a point p in the exterior E, on the plate P, or on the
baffle to the normal velocity v on the plate P.
where Gk(p,q) is a free-space Greens function for the
Helmholtz equation and G represents the whole
or part of the plate.
In this document the Green's function is defined as follows
Gk(p,q) =
1
4 p
eikr
r
(k Î \sf R+) ,
(13)
where r=|r|, r=p-q, \sf R+ is the set
of positive real numbers and i is the unit imaginary
number. The Green's function (13) also
satisfies the Sommerfeld radiation condition (6), ensuring that all
scattered and radiated waves are outgoing in the farfield.
Using the Rayleigh integral (11), the velocity potential
at any point in the exterior field can be computed
from the velocity v of the panel by a straightforward integration.
However, the velocity of the panel is only known at the
outset in cases when the Neumann condition
(a(p)=0 and b(p)=1 in (5)) is given.
In the case of other boundary conditions, the velocity
v of the panel must be determined first.
For example
if j is known on the panel then v needs to be obtained
on the panel first by solving the integral equation (11).
Once v is known on the panel, the velocity potential (or sound
pressure) can be determined throughout the field by (11).
In this work, the approach to solving (11)
with general boundary conditions (5) involves
applying the technique of collocation. (In the case of the
Neumann boundary condition, the technique reduces to product
integration.)
It can be observed that one potential difficulty could arise
in the numerical solution of equation (11);
in the Dirichlet problem the equation (11)
is a Fredholm integral equation of the first kind.
It is well-known that first kind equations generally
do not lend themselves to
computational solution (see [1], for example).
However, since the integrand
in (11) is singular, the equation can be solved
by typical integral equation methods such as collocation.
The method may be less accurate than you would
otherwise expect in this case, but the solution is still possible.